#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()
{
int a;
int b;
int n;
printf(“猜猜2022年11月哪一天会是你的lucky day\n开始咯,你有三次机会,猜吧(1~30):”);
a=rand()%31+1;
for(n=1;n<=3;n++){scanf(“%d”,&b);
if(n==3){
if(a>b)
printf(“你猜的日期早了,你的lucky day还没到呢\n”);
if(a<b)
printf(“你猜的日期晚了,你的lucy day已经过啦\n”);
if(a==b){
printf(“哇,猜中了:-)”);break;}break;
}
if(a>b)
printf(“你猜的日期早了,你的lucky day还没到呢\n再猜(1~30):”);
if(a<b)
printf(“你猜的日期晚了,你的lucy day已经过啦\n再猜(1~30):”);
if(a==b)
{
printf(“哇,猜中了:-)”);break;}
}
if(n=4)
printf(“次数用完啦。偷偷告诉你:11月,你的lucky day是8号”);
return 0;}
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <math.h>
int main()
{
char n;
n = getchar();
while (scanf_s(“%c”, & n) != EOF)
{
switch (n) {
case’r’:printf(“stop!”); getchar(); break;
case’g’:printf(“go go go”); getchar(); break;
case’y’:printf(“wait a minute”); getchar(); break;
default:printf(“something must be wrong…”); getchar(); break;
}
}
return 0;
}
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define N 5
int main()
{
int number;
int i;
srand(time(0));
for (i = 0; i < N; ++i)
{
number = rand() % 500 + 1;
printf(“20228329%04d\n”, number);
}
return 0;
}
#include<stdio.h>
int main()
{
int a, n, i;
double s, x1, x2;
while (scanf_s(“%d%d”, &n, &a) != EOF) {
x1 = 1;
x2 = a;
for (i = 1, s = 0; i <= n; i++) {
s = s + x1 / x2;
x1 = x1 + 1;
x2 = x2 * 10 + x2;
}
printf(“n=%d,a=%d,s=%.6f\n”, n, a, s);
}
return 0;
}
#include<stdio.h>
int main()
{
int line, a, s, i;
a = 1;
scanf_s(“%d”, &line);
for (; a <= line; a++) {
for (i = 1; i <= a; i++) {
s = i * a;
printf(“%d*%d=%d\t”, i, a, s);
}
printf(“\n”);
}
return 0;
}
#include<stdio.h>
int main()
{
int i, j, k, n;
scanf_s(“%d”, &n);
for (i = 1; i <= n; i++) {
for (j = 1; j < i; j++) {
printf(” \t”);
}
for (j = 1; j <= 2 * (n – i) + 1; j++) {
printf(” O \t”);
}
printf(“\n”);
for (j = 1; j < i; j++) {
printf(” \t”);
}
for (j = 1; j <= 2 * (n – i) + 1; j++) {
printf(“<H>\t”);
}
printf(“\n”);
for (j = 1; j < i; j++) {
printf(” \t”);
}
for (j = 1; j <= 2 * (n – i) + 1; j++) {
printf(“I I\t”);
}
printf(“\n”);
printf(“\n”);
}
return 0;
}
需要2(n-i)+1个字符小人
需要打印i-1个tab
原文地址:http://www.cnblogs.com/yuure/p/16819566.html