题目
编写一个程序,通过填充空格来解决数独问题。
数独的解法需 遵循如下规则:
数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3×3 宫内只能出现一次。(请参考示例图)
数独部分空格内已填入了数字,空白格用 ‘.’ 表示。
示例 1:
输入:board = [[“5″,”3″,”.”,”.”,”7″,”.”,”.”,”.”,”.”],[“6″,”.”,”.”,”1″,”9″,”5″,”.”,”.”,”.”],[“.”,”9″,”8″,”.”,”.”,”.”,”.”,”6″,”.”],[“8″,”.”,”.”,”.”,”6″,”.”,”.”,”.”,”3″],[“4″,”.”,”.”,”8″,”.”,”3″,”.”,”.”,”1″],[“7″,”.”,”.”,”.”,”2″,”.”,”.”,”.”,”6″],[“.”,”6″,”.”,”.”,”.”,”.”,”2″,”8″,”.”],[“.”,”.”,”.”,”4″,”1″,”9″,”.”,”.”,”5″],[“.”,”.”,”.”,”.”,”8″,”.”,”.”,”7″,”9″]]
输出:[[“5″,”3″,”4″,”6″,”7″,”8″,”9″,”1″,”2”],[“6″,”7″,”2″,”1″,”9″,”5″,”3″,”4″,”8”],[“1″,”9″,”8″,”3″,”4″,”2″,”5″,”6″,”7”],[“8″,”5″,”9″,”7″,”6″,”1″,”4″,”2″,”3”],[“4″,”2″,”6″,”8″,”5″,”3″,”7″,”9″,”1”],[“7″,”1″,”3″,”9″,”2″,”4″,”8″,”5″,”6”],[“9″,”6″,”1″,”5″,”3″,”7″,”2″,”8″,”4”],[“2″,”8″,”7″,”4″,”1″,”9″,”6″,”3″,”5”],[“3″,”4″,”5″,”2″,”8″,”6″,”1″,”7″,”9”]]
来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/sudoku-solver
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
递归+剪枝
- 解题思路
尝试穷举所有填写,并排除不可能的分支。玩数独的时候,首先会尝试填写所有确定的数字,以降低复杂度。对于无法确定的空格,进行尝试填写。填写后,可以根据当前填写的数字,再进行一遍填写确定数字。然后寻找下一个空格进行填写。
package l3;
import java.util.*;
public class demo37 {
public static void main(String[] args) {
// char[][] boardHang = new char[][]{
// {'5','3','.','.','7','.','.','.','.'},
// {'6','.','.','1','9','5','.','.','.'},
// {'.','9','8','.','.','.','.','6','.'},
// {'8','.','.','.','6','.','.','.','3'},
// {'4','.','.','8','.','3','.','.','1'},
// {'7','.','.','.','2','.','.','.','6'},
// {'.','6','.','.','.','.','2','8','.'},
// {'.','.','.','4','1','9','.','.','5'},
// {'.','.','.','.','8','.','.','7','9'}};
char[][] boardHang = new char[][]{
{'.','.','9','7','4','8','.','.','.'},
{'7','.','.','.','.','.','.','.','.'},
{'.','2','.','1','.','9','.','.','.'},
{'.','.','7','.','.','.','2','4','.'},
{'.','6','4','.','1','.','5','9','.'},
{'.','9','8','.','.','.','3','.','.'},
{'.','.','.','8','.','3','.','2','.'},
{'.','.','.','.','.','.','.','.','6'},
{'.','.','.','2','7','5','9','.','.'}};
solveSudoku(boardHang);
}
//块转行
// for (int i = 0; i < 9; i++) {
// for (int j = 0; j < 9; j++) {
// //i==0
// //hang_i 0,1,2
// //j=0-8
// //hang_j0_8 0,1,2 0,1,2
// //boardHang[i][j]=board[indexi][indexj];
// int indexi = (i/3)*3+j/3;
// int indexj = j%3;
// boardHang[i][j]=board[indexi][indexj];
// }
// }
//indexi=j/3+i/3*3;
//indexj=j%3+(i%3)*3;
//boardLie[i][j] = board[j][i];
static char[][] rs= new char[9][9];
public static void solveSudoku(char[][] board) {
char[][] boardBlock = new char[9][9];
char[][] boardLie = new char[9][9];
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
int indexi,indexj;
indexi=j/3+i/3*3;
indexj=j%3+(i%3)*3;
boardBlock[i][j] = board[indexi][indexj];
}
}
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
boardLie[i][j] = board[j][i];
}
}
while (true)
{
int count = 0;
for (int i = 0; i < 9; i++) {
count+=getTrueNumber(i ,board,boardBlock,boardLie);
}
if(count==0)
{
break;
}
}
char[][] newBoard = copyBoard(board);
rs = copyBoard(board);
dfs(newBoard,boardBlock,boardLie,0,0);
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
board[i][j]=rs[i][j];
}
}
printBoard(board);
}
public static void dfs(
char[][] newBoard,char[][] newBoardBlock,char[][] newBoardLie,
int x,int y)
{
boolean allFill=true;
for (int i = 0; i < 9; i++) {
if(allFill)
{
for (int j = 0; j < 9; j++) {
if(rs[i][j]=='.')
{
allFill=false;
break;
}
}
}
}
if(allFill)
{
return;
}
if(x==9& y==0)
{
rs=newBoard;
return ;
}
for (int i = x; i < 9; i++) {
for (int j = y; j < 9; j++) {
int o=i;
int p=j;
p--;
if(p<0)
{
p=8;
o--;
}
if(o>-1)
{
if(newBoard[o][p]=='.')
{
return;
}
}
if(newBoard[i][j]!='.' && (i==8 && j==8))
{
rs=newBoard;
return;
}
else if(newBoard[i][j]!='.')
{
continue;
}
List<Character> canUseNumber = getCanUseNumber(newBoard, i, j, newBoardBlock, newBoardLie);
if(canUseNumber.size()==0)
{
return;
}
for (Character num: canUseNumber
) {
char[][] newBoardCopy = copyBoard(newBoard);
char[][] newBoardBlockCopy = copyBoard(newBoardBlock);
char[][] newBoardLieCopy = copyBoard(newBoardLie);
int indexi,indexj;
indexi=j/3+i/3*3;
indexj=j%3+(i%3)*3;
newBoardCopy[i][j]=num;
newBoardLieCopy[j][i]=num;
newBoardBlockCopy[indexi][indexj]=num;
while (true)
{
int count = 0;
for (int m = 0; m < 9; m++) {
count+=getTrueNumber(m ,newBoardCopy,newBoardBlockCopy,newBoardLieCopy);
}
if(count==0)
{
break;
}
}
int m=i;
int n=j+1;
if(n==9)
{
n=0;
m++;
}
dfs(newBoardCopy,newBoardBlockCopy,newBoardLieCopy,m,n);
}
}
}
}
public static char[][] copyBoard(char[][] board)
{
char[][] newBoard = new char[board.length][board[0].length];
for (int i = 0; i < board.length; i++) {
for (int j = 0; j < board[0].length; j++) {
newBoard[i][j]=board[i][j];
}
}
return newBoard;
}
private static void printBoard(char[][] board)
{
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
if(j%3==0)
{
System.out.print(" ");
}
System.out.print(board[i][j]);
}
System.out.println();
}
}
private static List<Character> getCanUseNumber(char[][] board,int pointX,int pointY,char[][] boardBlock,char[][] boardLie)
{
List<Character> list= new ArrayList<>();
list.add('1');
list.add('2');
list.add('3');
list.add('4');
list.add('5');
list.add('6');
list.add('7');
list.add('8');
list.add('9');
removeUsedNumber(board, pointX, list);
int indexI =pointY/3+pointX/3*3;
removeUsedNumber(boardBlock, indexI, list);
removeUsedNumber(boardLie, pointY, list);
return list;
}
private static void removeUsedNumber(char[][] board, int pointX, List<Character> list) {
for (int i = 0; i < 9; i++) {
if(board[pointX][i]!='.')
{
for (Character c:
list) {
if(c.charValue()==board[pointX][i])
{
list.remove(c);
break;
}
}
}
}
}
//0 1 2 x/3*3-------+2
//3 4 5
//6 7 8
//0 1 2,0 3 6;0
//0 1 2,1 4 7;1
//0 1 2,2 5 8;2
//
private static int getTrueNumber(int pointX,char[][] board ,char[][] boardBlock,char[][] boardLie)
{
int count=0;
int[] x= new int[3];
x[0] = pointX/3*3;
x[1] = x[0]+1;
x[2] = x[1]+1;
int[] y= new int[3];
y[0]=pointX;
getYStartIndex(y);
HashMap<Character,NumCountPoint> numCount = new HashMap<>();
getNumCount(pointX, boardBlock, x, numCount,0);
getNumCount(pointX, boardBlock, y, numCount,1);
HashSet<Character> targetSet = new HashSet<>();
for (int i = 0; i < 9; i++) {
if(boardBlock[pointX][i]!='.')
{
targetSet.add(boardBlock[pointX][i]);
}
}
for (Character c: numCount.keySet()
) {
if(targetSet.contains(c))
{
continue;
}
else
{
NumCountPoint numCountPoint= numCount.get(c);
ArrayList<Integer> canUseIndex = new ArrayList<Integer>();
for (int i=0;i<9;i++)
{
if(boardBlock[pointX][i]=='.')
{
canUseIndex.add(i);
}
}
for (Point p:numCountPoint.points
) {
if(p.xy==0)
{
int start = p.pointY/3*3;
for (int i = 0; i < 3; i++) {
int index = canUseIndex.indexOf(start + i);
if (index > -1) {
canUseIndex.remove(index);
}
}
}
else
{
int[] delY= new int[3];
delY[0]=p.pointY;
getYStartIndex(delY);
for (int i:delY
) {
int index = canUseIndex.indexOf(i);
if (index > -1) {
canUseIndex.remove(index);
}
}
}
}
if(canUseIndex.size()==1)
{
int blockX= pointX;
int blockY = canUseIndex.get(0);
int indexI,indexJ;
indexI=blockY/3+blockX/3*3;
indexJ=blockY%3+(blockX%3)*3;
List<Character> canUseNumber = getCanUseNumber(board, indexI, indexJ, boardBlock, boardLie);
if(canUseNumber.contains(c))
{
boardBlock[blockX][blockY]=c;
board[indexI][indexJ]=c;
boardLie[indexJ][indexI]=c;
count++;
}
}
}
}
return count;
}
private static void getYStartIndex(int[] y) {
while (true)
{
if(y[0]-3>=0)
{
y[0]=y[0]-3;
}
else
{
break;
}
}
y[1]=y[0]+3;
y[2]=y[1]+3;
}
public static class NumCountPoint
{
char c;
int count;
List<Point> points;
}
public static class Point
{
char c;
int pointX;
int pointY;
//0代表水平x
//1代表竖直y
int xy;
}
private static void getNumCount(int pointX, char[][] boardBlock, int[] x, HashMap<Character, NumCountPoint> numCount,int xy) {
for (int xIndex:x
) {
if(xIndex!=pointX)
{
for (int i = 0; i < 9; i++) {
if(boardBlock[xIndex][i]!='.')
{
char c = boardBlock[xIndex][i];
Point point = new Point();
NumCountPoint numCountPoint;
if(!numCount.containsKey(c))
{
numCountPoint = new NumCountPoint();
numCountPoint.points= new ArrayList<>();
numCountPoint.c=c;
numCountPoint.count=1;
}
else
{
numCountPoint = numCount.get(c);
numCountPoint.count=1+numCountPoint.count;
}
point.c=c;
point.pointX=pointX;
point.pointY=i;
point.xy=xy;
numCountPoint.points.add(point);
numCount.put(c,numCountPoint);
}
}
}
}
}
}
递归回溯
- 解题思路
尝试填写一个数字,然后如果在后续填写中发现不对就回溯当前状态。
package l3;
public class demo37_2 {
public static void main(String[] args) {
char[][] boardHang = new char[][]{
{'.','.','9','7','4','8','.','.','.'},
{'7','.','.','.','.','.','.','.','.'},
{'.','2','.','1','.','9','.','.','.'},
{'.','.','7','.','.','.','2','4','.'},
{'.','6','4','.','1','.','5','9','.'},
{'.','9','8','.','.','.','3','.','.'},
{'.','.','.','8','.','3','.','2','.'},
{'.','.','.','.','.','.','.','.','6'},
{'.','.','.','2','7','5','9','.','.'}};
solveSudoku(boardHang);
}
public static void solveSudoku(char[][] board)
{
//num是1-9,所示col需要到10
boolean[][] rowUsed= new boolean[9][10];
boolean[][] colUsed=new boolean[9][10];
boolean[][][] blockUsed = new boolean[3][3][10];
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
//字符相减,巧取num数字
//字符"."减字符0,num肯定不在1-9之间
int num = board[i][j]-'0';
if(num>=1 && num<=9)
{
rowUsed[i][num]=true;
colUsed[j][num]=true;
blockUsed[i/3][j/3][num]=true;
}
}
}
dfs(board,rowUsed,colUsed,blockUsed,0,0);
printBoard(board);
}
private static void printBoard(char[][] board)
{
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
if(j%3==0)
{
System.out.print(" ");
}
System.out.print(board[i][j]);
}
System.out.println();
}
}
public static boolean dfs(char[][] board,boolean[][] rowUsed,boolean[][] colUsed,boolean[][][] blockUsed,int row,int col)
{
if(col==9)
{
col=0;
row++;
if(row==9)
{
return true;
}
}
//如果是点尝试进行填充,否则跳过进行下一个位置
if(board[row][col]=='.')
{
//1-9尝试填充
for (int num = 1; num <= 9; num++) {
//行列块都没用过,才能使用这个数字
boolean canUsed= !(rowUsed[row][num] || colUsed[col][num] || blockUsed[row/3][col/3][num]);
if(canUsed)
{
rowUsed[row][num]=true;
colUsed[col][num]=true;
blockUsed[row/3][col/3][num]=true;
board[row][col]=(char)('0'+num);//巧取char
//dfs 注意col不能++,回溯之后,还要用到col呢
if(dfs(board,rowUsed,colUsed,blockUsed,row,col+1))
{
//回溯出口
return true;
}
//失败了,重置当前状态,尝试填下一个数字
rowUsed[row][num]=false;
colUsed[col][num]=false;
blockUsed[row/3][col/3][num]=false;
board[row][col]='.';//巧取char
}
}
}
else
{
return dfs(board,rowUsed,colUsed,blockUsed,row,col+1);
}
return false;
}
}
原文地址:http://www.cnblogs.com/huacha/p/16858286.html