UnicodeDecodeError:’gbk’ codec can’t decode byte 0x80 in position 0 illegal multibyte sequence

 

回答1

if you will open file with utf-8,then you need write:

open(file_name, 'r', encoding='UTF-8')

if you will open file with GBK,then you need do:

open(file_name, 'rb')

hope to solve your problem!

 

FileNotFoundError: [Errno 2] No such file or directory [duplicate]

回答1

For people who are still getting error despite of passing absolute path, should check that if file has a valid name. For me I was trying to create a file with ‘/’ in the file name. As soon as I removed ‘/’, I was able to create the file. 

 

 

[Solved] OSError errno22 invalid argument

 

Let us try to understand it with the help of an example. The below code has been executed in python shell to access local files. First, we shall import the pandas file to use read_csv()

1
import pandas as pd

Now, we shall try to access a csv file.

1
file = read_csv("C:\textfile.csv")

The above line of code will raise the below error.

OSError: [Errno 22] Invalid argument: 'C:\textfile.csv' 

The reason behind the error is that python does not consider the backslash. Because of that, it showed oserror invalid argument. So what we have to do is that instead of a backslash, we have to replace it with a forwarding slash.

1
file = read_csv("C:/textfile.csv")

Th error has been resolved now.

 

原文地址:http://www.cnblogs.com/chucklu/p/16905434.html

1. 本站所有资源来源于用户上传和网络,如有侵权请邮件联系站长! 2. 分享目的仅供大家学习和交流,请务用于商业用途! 3. 如果你也有好源码或者教程,可以到用户中心发布,分享有积分奖励和额外收入! 4. 本站提供的源码、模板、插件等等其他资源,都不包含技术服务请大家谅解! 5. 如有链接无法下载、失效或广告,请联系管理员处理! 6. 本站资源售价只是赞助,收取费用仅维持本站的日常运营所需! 7. 如遇到加密压缩包,默认解压密码为"gltf",如遇到无法解压的请联系管理员! 8. 因为资源和程序源码均为可复制品,所以不支持任何理由的退款兑现,请斟酌后支付下载 声明:如果标题没有注明"已测试"或者"测试可用"等字样的资源源码均未经过站长测试.特别注意没有标注的源码不保证任何可用性